To rule out the square root of any number other than 10 seconds calculator (square root a number within 10 seconds)

To rule out the square root of any number other than 10 seconds calculator (square root a number within 10 seconds)




To rule out the square root of a number without a calculator
without a calculator to find the square root of any number of leveraged this trick for our small numbers at the beginning of class, a list will be made. Down the list provided below: 1 = 01 = 04 X 3 = 09 4 = 16 5 5 = 6 = 36 = 49 7 64 8 = 9 = 81 notice can be seen, the last digit of each of the squares are written in bold colors. Ankatii use our trick at the end. Now, to get to the square root of 576, we'll learn how to quickly and without a calculator to find the square root. 1) Our first question will be to work with the last digit of the number. That number to 576 in the last 6; The 6 digit number of our first orders there is no list, I find out. 1 = 01 = 04 X 3 = 09 4 = 16 5 5 = 6 = 36 = 49 7 64 8 = 9 = 81 list are two bargeh 6 16 and at 36. The square root of 4 and 6, respectively, so our results should be an end to that number 4 or 6; What will happen is that we'll get to the next step. B) the last two address the question of the number should be cut. Their job is done. Now, with the first address. Let's cut the last two 576 address. Only 5 of the work. Our first list of no less than 5 square formed, it looked at. 1 = 01 = 04 X 3 = 09 turns, 04 is less than 5, the next step 09, which is less than 5 large, it can not be taken. so, take the square root of 04. This is the address of our results. 3) will be the result if 4 or 6; 4 or 6 will be the end of it, but we do not know yet. If you assume that, what will happen at the end. 4) in the end result will be smaller math (4), it would be larger (6), in order to learn the results of the first two digits of the serial number of times to be with. And multiplied by the number of questions with the first drawing to compare. The first question to address is smaller than the product, and the last number to be chotatii first address the question of multiplying the end result will be greater than if you address baratii. Now, the next number of how many? 3; If 2X3 = 6; The first address this question than 6 5 short. So the end result will address chotatii between 4 and 6. In other words, 4; 4 Therefore, the results may seem to fall so far, it is very difficult. But it really is not difficult. Take it easy if you practice a few times. I took a four-digit number. For example, will have to find the square root of 1849. 1) the last digit of the work. End address 9; There are no numbers to the list of 9 square? 3 = 09 7 = 49 , so our results will address the last 3 or 7; ii) the end of 1849, I cut two address. The first two address only takes 18; This must be 18 to work with. Bargasankhyati has no less than 18 on the list, therefore a 1 = 01 = 04 X 3 = 09 4 = 16 5 = 5 5 is greater than 18, and 16 small. Take the square root of 16 is 4. This results in the first 4 digits. 3) If the results of our 43 or 47; What take? The first address of 4, 5, and serial number; The quality here: 4X5 = 0. The first two questions address 18 but smaller than 0. So ankatio'll end small. In other words, between 3 and 7 small 3; 43 Therefore, the results of any of the numbers (the square root of an integer), the square root can be traced. Hopefully, the two examples are easy to understand. 2025 and 3364 the number of the square root of two methods to get the word out to readers gave responsibility.